AP EAMCET · Maths · Circle
If the length of the tangent drawn from the point from \((-2,3)\) to the circle \(x^2+y^2+8 x\) \(-6 y+k=0\) is 4 units, then \(k\) is equal to
- A 34
- B 36
- C 38
- D 37
Answer & Solution
Correct Answer
(D) 37
Step-by-step Solution
Detailed explanation
Circle \(C: x^2+y^2+8 x-6 y+k=0\) Length of tangents drawn by an external points to the circle is \(\sqrt{S_1}\). Now, the length of tangent drawn by \((-2,3)\) to the circle is \(L\),…
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