AP EAMCET · PHYSICS · Current Electricity
Charge passing through a conductor of cross-section \(0.3 \mathrm{~m}^2\) is given by \(\mathrm{q}=\left(3 \mathrm{t}^2+5 \mathrm{t}+2\right) \mathrm{C}\) where ' \(\mathrm{t}\) ' is in seconds. The drift velocity at \(t=2 \mathrm{~s}\) is
(Concentration of electrons in the conductor \(=2 \times 10^{25} \mathrm{~m}^{-3}\) )
- A \(0.77 \times 10^{-5} \mathrm{~ms}^{-1}\)
- B \(0.93 \times 10^{-5} \mathrm{~ms}^{-1}\)
- C \(1.77 \times 10^{-5} \mathrm{~ms}^{-1}\)
- D \(2.08 \times 10^{-5} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.77 \times 10^{-5} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, area of cross-section \(\mathrm{A}=0.3 \mathrm{~m}^2\),…
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