AP EAMCET · Maths · Circle
The length of the tangent drawn from any point on the circle \(x^2+y^2+2 g x+2 f y+c_1=0\) to the circle \(x^2+y^2+2 g x+2 f y+c_2=0\) is
- A \(\sqrt{C_2-c_1}\)
- B \(\sqrt{c_1^2+c_2^2}\)
- C \(c_1+c_2\)
- D \(c_1-c_2\)
Answer & Solution
Correct Answer
(A) \(\sqrt{C_2-c_1}\)
Step-by-step Solution
Detailed explanation
Circles are \(\begin{aligned} & C_1 \equiv x^2+y^2+2 g x+2 f y+c_1=0 \\ \text {and } & C_2 \equiv x^2+y^2+2 g x+2 f y+c_2=0 \end{aligned}\) Clearly circles are concentric, Clearly, length of tangent is…
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