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AP EAMCET · Maths · Straight Lines

The circumcentre of the triangle formed by the points \(A(1, \sqrt{3}), B(-1,-\sqrt{3})\) and \((3,-\sqrt{3})\) is

  1. A \((1,-\sqrt{3})\)
  2. B \(\left(-1, \frac{1}{\sqrt{3}}\right)\)
  3. C \((0,0)\)
  4. D \(\left(1, \frac{-1}{\sqrt{3}}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left(1, \frac{-1}{\sqrt{3}}\right)\)

Step-by-step Solution

Detailed explanation

Vertices of \(\triangle A B C\) are \(A(1, \sqrt{3}), B(-1,-\sqrt{3})\) and \(C(3,-\sqrt{3})\) \(A B=\sqrt{4+12}=4\) \(\begin{aligned} & B C=\sqrt{4+12}=4 \\ & A C=\sqrt{4+12}=4\end{aligned}\) Here, \(A B C\) is an equilateral triangle. \(\therefore\) Circumcentre of triangle is…