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AP EAMCET · Maths · Circle

If the chord of contact of the point \(\mathrm{P}(1,1)\) with respect to the circle \(S=x^2+y^2+4 x+6 y-3=0\) meet the circle \(\mathrm{S}=0\) at \(\mathrm{A}\) and \(\mathrm{B}\), then the area of \(\triangle \mathrm{PAB}\) is

  1. A \(\frac{216}{25}\)
  2. B \(\frac{108}{25}\)
  3. C \(\frac{27}{25}\)
  4. D \(\frac{54}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{108}{25}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { } S=x^2+y^2+4 x+6 y-3=0 \\ & \Rightarrow(x+2)^2+(y+2)^2=4^2\end{aligned}\)…