AP EAMCET · Maths · Circle
If the chord of contact of the point \(\mathrm{P}(1,1)\) with respect to the circle \(S=x^2+y^2+4 x+6 y-3=0\) meet the circle \(\mathrm{S}=0\) at \(\mathrm{A}\) and \(\mathrm{B}\), then the area of \(\triangle \mathrm{PAB}\) is
- A \(\frac{216}{25}\)
- B \(\frac{108}{25}\)
- C \(\frac{27}{25}\)
- D \(\frac{54}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{108}{25}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } S=x^2+y^2+4 x+6 y-3=0 \\ & \Rightarrow(x+2)^2+(y+2)^2=4^2\end{aligned}\)…
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