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AP EAMCET · Maths · Properties of Triangles

If \(A B C\) is a right angled triangle with \(90^{\circ}\) at \(C\) and \(a>b\), then \(\frac{a^2+b^2}{a^2-b^2} \sin (A-B)=\)

  1. A \(\frac{3}{2}\)
  2. B 1
  3. C \(\frac{1}{2}\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(B) 1

Step-by-step Solution

Detailed explanation

On applying sine rule, we get…