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AP EAMCET · Maths · Circle

If \(S \equiv 2 x^2+2 y^2-8 x+8 y-7=0\) is the circle passing through the points of intersection of the circles \(x^2+y^2+\) \(\mathrm{kx}-\mathrm{ky}+1=0\) and \(\mathrm{x}^2+\mathrm{y}^2-\mathrm{kx}+\mathrm{ky}-2=0\), then the length of the tangent drawn from the point \((k, k)\) to the circle \(\mathrm{S}\) is

  1. A \(\frac{3}{\sqrt{2}}\)
  2. B 3
  3. C \(\sqrt{\frac{23}{2}}\)
  4. D \(\sqrt{23}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{3}{\sqrt{2}}\)

Step-by-step Solution

Detailed explanation

The equation of circle through points of intersection of \(S_1, S_2\) is:…