AP EAMCET · Maths · Three Dimensional Geometry
If \(A=(1,8,4), B=(2,-3,1)\), then the direction cosines of a normal to the plane \(A O B\) is
- A \(\frac{2}{\sqrt{78}}, \frac{5}{\sqrt{78}}, \frac{-7}{\sqrt{78}}\)
- B \(\frac{2 \sqrt{10}}{9}, \frac{7 \sqrt{10}}{90}, \frac{-19 \sqrt{10}}{90}\)
- C \(\frac{4}{\sqrt{218}}, \frac{9}{\sqrt{218}}, \frac{-11}{\sqrt{218}}\)
- D \(\frac{2}{11}, \frac{6}{11}, \frac{-9}{11}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \sqrt{10}}{9}, \frac{7 \sqrt{10}}{90}, \frac{-19 \sqrt{10}}{90}\)
Step-by-step Solution
Detailed explanation
Given, \(A=(1,8,4)\) and \(B=(2,-3,1)\)…
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