AP EAMCET · Maths · Complex Number
\[
(1+i)^{2024}+(1-i)^{2024}=
\]
- A \(-2^{1012}\)
- B \(2^{1013}\)
- C \(2^{2024} \mathrm{i}\)
- D \(-2^{1012} \mathrm{i}\)
Answer & Solution
Correct Answer
(B) \(2^{1013}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { }(1+i)^{2024}+(1+i)^{2024}=\left[(1+i)^2\right]^{1012}+\left[(1-i)^2\right]^{1012} \\ & =\left[(2 i)^{1012}\right]+[(-2 i)]^{1012} \\ & =(2)^{1012}(i)^{1012}+(-2)^{1012}(i)^{1012} \\ & =2 \cdot 2^{1012}=2^{1013}\end{aligned}\)
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