AP EAMCET · Maths · Basic of Mathematics
If \(x, y\) are two positive integers such that \(x+y=20\) and the maximum value of \(x^3 y\) is \(k\) at \(x=\alpha, y=\beta\) then \(\frac{k}{\alpha^2 \beta^2}=\)
- A \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)
- B \(\frac{\alpha}{\beta}-\frac{\beta}{\alpha}\)
- C \(\frac{\alpha}{\beta}\)
- D \(\frac{\alpha+\beta}{\alpha \beta}\)
Answer & Solution
Correct Answer
(C) \(\frac{\alpha}{\beta}\)
Step-by-step Solution
Detailed explanation
\(x+y=20\) \(\frac{\frac{x}{3}+\frac{x}{3}+\frac{x}{3}+y}{4} \geq\left[\left(\frac{x}{3}\right)^3 y\right]^{1 / 4} \Rightarrow 5 \geq\left(\frac{x^3 y}{3^3}\right)^{\frac{1}{4}}\)…
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