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AP EAMCET · Maths · Three Dimensional Geometry

Let \(\mathrm{L}\) be the line passing through the points \(\hat{\mathrm{i}}-9 \hat{\mathrm{k}}\) and \(7 \hat{j}+\hat{k}\) and \(\pi\) be the plane passing through the point \(6 \hat{i}+\hat{j}\) and perpendicular to the vector \(\hat{i}+\hat{j}+\hat{k}\). If \(\theta\) is the angle between \(\mathrm{L}\) and \(\pi\), then \(\sin \theta=\)

  1. A \(\frac{8 \sqrt{2}}{15}\)
  2. B \(\frac{3 \sqrt{3}}{8}\)
  3. C \(\frac{7}{13}\)
  4. D \(\frac{24}{25}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{8 \sqrt{2}}{15}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text {} \mathrm{L}: \vec{r}=\vec{a}+\lambda(\vec{b}-\vec{a}) \\ & \Rightarrow \vec{r}=(\hat{i}-9 \hat{k})+\lambda(\hat{i}-9 \hat{k}-7 \hat{j}-\hat{k})\\ & \Rightarrow \vec{r}=(\hat{i}-9 \hat{k})+\lambda(\hat{i}-7 \hat{j}-10 \hat{k})...(i) \\ & \pi: \vec{r}…