AP EAMCET · Maths · Probability
If four dice are thrown simultaneously, then the probability that none of the dice shows the number 1 on its face, is
- A \(\frac{625}{1296}\)
- B \(\frac{125}{648}\)
- C \(\frac{1250}{1296}\)
- D \(\frac{625}{2592}\)
Answer & Solution
Correct Answer
(A) \(\frac{625}{1296}\)
Step-by-step Solution
Detailed explanation
Since there are 6 total samples. Hence the probability of getting number 1 on face \(=\frac{1}{6}\) \(\therefore\) Probability of not getting number 1 on face of a dice \(=1-\frac{1}{6}=\frac{5}{6}\) Since 4 dice are thrown simultaneously. Hence probability of not getting number…
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