AP EAMCET · Maths · Application of Derivatives
If the curves \(2 x^2+k y^2=30\) and \(3 y^2=28 x\) cut each other orthogonally, then \(k=\)
- A \(5\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
\(2 x^2+k y^2=30\) ...(i) \(\Rightarrow 4 x+2 k y \frac{d y}{d x}=0 \Rightarrow \frac{d y}{d x}=\frac{-2 x}{k y}=m_1\) And \(3 y^2=28 x\) ...(ii) \(\Rightarrow 6 y \frac{d y}{d x}=28 \Rightarrow \frac{d y}{d x}=\frac{14}{3 y}=m_2\) Since, curves cut orthogonally…
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