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AP EAMCET · Maths · Differentiation

If f"(x) is continuous at x=0 and f"(0)=4, then find the following value of limx02fx-3f2x+f4xx2

  1. A 4
  2. B 8
  3. C 12
  4. D 16
Verified Solution

Answer & Solution

Correct Answer

(C) 12

Step-by-step Solution

Detailed explanation

We have, limx→02fx-3f2x+f4xx2, putting x=0, we get 00 form. So, Applying L'Hospital rule limx→02fx-3f2x+f4xx2=limx→02f'x-6f'2x+4f'4x2x again, apply L'Hospital rule, limx→02fx-3f2x+f4xx2=limx→02f''x-12f''2x+16f''4x2 Putting x=0, we get…