AP EAMCET · Chemistry · Structure of Atom
If the electronic configuration of \(M^{3+}\) is [Xe] \(4 f^3\), then \(M^{3+}\) is
- A \(\mathrm{Nd}^{3+}\)
- B \(\mathrm{Pr}^{3+}\)
- C \(\mathrm{Sm}^{3+}\)
- D \(\mathrm{Dy}^{3+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Nd}^{3+}\)
Step-by-step Solution
Detailed explanation
Given, the electronic configuration of \(M^{3+}\) is [Xe] \(4 \int^3\). The electronic configuration of metals given in options in \(\mathrm{M}^{3+}\) are as follows: (a) \(\mathrm{Nd}^{3+}=[\mathrm{Xe}] 4 f^3\) (b) \(\operatorname{Pr}^{3+}=[\mathrm{Xe}] 4 f^2\) (c)…
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