AP EAMCET · Maths · Application of Derivatives
If \((2, a)\) and \((b, 19)\) are two stationary points of the curve \(y=2 x^3-15 x^2+36 x+c\), then \(a+b+c=\)
- A \(-20\)
- B \(15\)
- C \(-12\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(15\)
Step-by-step Solution
Detailed explanation
Given the function \(y=2 x^3-15 x^2+36 x+C\) Now, \(\frac{d y}{d x}=6 x^2-30 x+36\) For stationary points, \(\frac{d y}{d x}=0\) \(6 x^2-3 x+36 \Rightarrow(x-2)(x-3)=0 \Rightarrow x=2,3\) So \(b=3\) \(\Rightarrow 19=2 \times 27-15 \times 9+36 \times 3+c \Rightarrow c=-8\) and…
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