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AP EAMCET · Maths · Straight Lines

The triangle formed by \(x^2-4 x y+y^2=0\) and \(x+y+4 \sqrt{6}=0\) is

  1. A an equilateral triangle
  2. B a right angled triangle
  3. C an isosceles triangle
  4. D a scalene triangle
Verified Solution

Answer & Solution

Correct Answer

(A) an equilateral triangle

Step-by-step Solution

Detailed explanation

\(x^2-4 x y+y^2=0\) \(\Rightarrow y^2-2 \cdot 2 x y+4 x^2=3 x^2\) \(\begin{array}{ll}\Rightarrow & (y-2 x)^2=3 x^2 \\ \Rightarrow & y-2 x= \pm \sqrt{3} x\end{array}\) \(y=(2 \pm \sqrt{3}) x\) \(\therefore\) The given triangle is an equilateral triangle.