AP EAMCET · Maths · Vector Algebra
If \(\overrightarrow{A B}=2 \hat{i}+3 \hat{j}-6 \hat{k} ; \overrightarrow{B C}=6 \hat{i}-2 \hat{j}+3 \hat{k}\) are the vectors along two sides of a triangle ABC , then perimeter of triangle ABC is:
- A 21
- B \(\sqrt{74}+14\)
- C \(\sqrt{74}+19\)
- D \(\sqrt{74}+3\)
Answer & Solution
Correct Answer
(B) \(\sqrt{74}+14\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{A B}=2 \hat{i}+3 \hat{j}-6 \hat{k} ; \overrightarrow{B C}=6 \hat{i}-2 \hat{j}+3 \hat{k}\) \(\overrightarrow{A C}=\overrightarrow{A B}+\overrightarrow{B C}=8 \hat{i}+\hat{j}-3 \hat{k}\) Perimeter of \(\triangle A B C\)…
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