AP EAMCET · Maths · Matrices
If \(A=\left[\begin{array}{cc}1 & 0 \\ 0 & -1\end{array}\right], P=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]\) and \(X=A P A^T\), then \(A^T X^{50} A=\)
- A \(\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]\)
- B \(\left[\begin{array}{cc}2 & 1 \\ 0 & -1\end{array}\right]\)
- C \(\left[\begin{array}{cc}25 & 1 \\ 1 & -25\end{array}\right]\)
- D \(\left[\begin{array}{cc}1 & 50 \\ 0 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{cc}1 & 50 \\ 0 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
Given matrix \(A=\left[\begin{array}{cc}1 & 0 \\ 0 & -1\end{array}\right]\) is orthogonal matrix, because \(A A^T=I\).…
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