AP EAMCET · Maths · Complex Number
If \(z=x+i y, x^2+y^2=1\) and \(z_1=z e^{i \theta}\) then \(\frac{z_1^{2 n}-1}{z_1^{2 n}+1}=\)
- A \(-i \tan n\left(\theta+\tan ^{-1}\left(\frac{y}{x}\right)\right)\)
- B \(i \cot \left(n\left(\theta+\tan ^{-1} \frac{y}{x}\right)\right)\)
- C \(i \tan n\left(\theta+\tan ^{-1} \frac{x}{y}\right)\)
- D \(i \tan \left(n\left(\theta+\tan ^{-1} \frac{y}{x}\right)\right)\)
Answer & Solution
Correct Answer
(D) \(i \tan \left(n\left(\theta+\tan ^{-1} \frac{y}{x}\right)\right)\)
Step-by-step Solution
Detailed explanation
\(z=x+i y=e^{i \phi}\)…
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