AP EAMCET · Maths · Determinants
If \(A\) and \(B\) are two square matrices with \(\operatorname{det} A=5\) and \(\operatorname{det}\left(B^T \cdot A^T\right)=-15\), then \(\operatorname{det} B\) is equal to
- A 3
- B -3
- C 0
- D 1
Answer & Solution
Correct Answer
(B) -3
Step-by-step Solution
Detailed explanation
Given, \(|A|=5 ;\left|B^T A^T\right|=-15\) We know \(|A|=\left|A^T\right|\) \(\begin{aligned} \therefore \quad\left|B^T\right|\left|A^T\right| & =|B||A|=-15 \\ |B| & =\frac{-15}{|A|}=\frac{-15}{5}=-3\end{aligned}\)
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