AP EAMCET · Chemistry · General Organic Chemistry
In Dumas method, \(0.3 \mathrm{~g}\) of an organic compound gave \(45 \mathrm{~mL}\) of nitrogen at STP. The percentage of nitrogen is
- A \(16.9\)
- B \(18.7\)
- C \(23.2\)
- D \(29.6\)
Answer & Solution
Correct Answer
(B) \(18.7\)
Step-by-step Solution
Detailed explanation
In Dumes method, \(\%\) of nitrogen \(=\frac{28 \mathrm{~V} \times 100}{22400 \times W}=\frac{28 \times 45 \times 100}{22400 \times 0.3}=18.75\)
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