AP EAMCET · Maths · Ellipse
The distance between the directrices of the ellipse \(\frac{x^2}{36}+\frac{y^2}{20}=1\) is
- A \(9\)
- B \(6 \sqrt{5}\)
- C \(8\)
- D \(3 \sqrt{5}\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
for \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 \Rightarrow \frac{x^2}{36}+\frac{y^2}{20}=1\) eccentricity \((e)=\sqrt{1-\frac{b^2}{a^2}}=\sqrt{1-\frac{20}{36}}\) \(=\frac{2}{3}\) Equation of directrix is \(x= \pm a e\)…
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