AP EAMCET · Maths · Definite Integration
\(\begin{aligned} & \lim _{n \rightarrow \infty} n\left[\frac{1}{\left(3 n^2+8 n+4\right)}+\frac{1}{3 n^2+16 n+16}+\ldots\right. \\ & \left.+\frac{1}{15 n^2}\right]=\end{aligned}\)
- A \(\frac{1}{2} \log \frac{9}{5}\)
- B \(\frac{1}{4} \log \frac{9}{5}\)
- C \(2 \log \frac{9}{5}\)
- D \(\frac{1}{4} \log \frac{5}{9}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{4} \log \frac{9}{5}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \lim _{n \rightarrow \infty} n\left[\frac{1}{3 n^2+8 n+4}+\frac{1}{3 n^2+16 n+16}+\ldots+\frac{1}{15 n^2}\right] \\ & =\lim _{n \rightarrow \infty} n \sum_{r=1}^n \frac{1}{3 n^2+8 n r+(2 r)^2} \\ & =\lim _{n \rightarrow \infty} \frac{1}{n} \sum_{r=1}^n…
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