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AP EAMCET · Maths · Definite Integration

If \(A=\int_1^{\sin \theta} \frac{t}{1+t^2} d t\) and \(B=\int_1^{\operatorname{cosec} \theta} \frac{1}{t\left(1+t^2\right)} d t\) then the value of \(\left|\begin{array}{ccc}A & A^2 & B \\ e^{A+B} & B^2 & -1 \\ 1 & A^2+B^2 & -1\end{array}\right|=\)

  1. A \(\sin \theta\)
  2. B \(\operatorname{cosec} \theta\)
  3. C 0
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) 0

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