AP EAMCET · Maths · Quadratic Equation
The number of solutions for the equation \(x^2-5|x|+6=0\) is .........
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Given equation \[ \begin{aligned} & x^2-5|x|+6=0 \\ & \Rightarrow \quad|x|^2-5|x|+6=0 \\ & \Rightarrow \quad(|x|-3)(|x|-2)=0 \\ & \Rightarrow \quad|x|=2 \text { or } 3 \\ & \Rightarrow \quad x= \pm 2, \pm 3 \\ & \end{aligned} \] \(\therefore\) There are 4 solutions.
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