AP EAMCET · Maths · Circle
Angle between the circles \(x^2+y^2-4 x-6 y-3=0\) and \(x^2+y^2+8 x-4 y+11=0\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \quad \mathrm{S}_1 \equiv x^2+y^2-4 x-6 y-3=0 \\ & \mathrm{~S}_2 \equiv x^2+y^2+8 x-4 y-11=0 \\ & \left(g_1, f_1, c_1\right)=(-2,-3,-3) \text { and }\left(g_2, f_2, c_2\right)=(4,-2,11) \end{aligned}\) Angle between two circles is given by…
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