AP EAMCET · Maths · Vector Algebra
The vector \(\mathbf{x}\) is perpendicular to the vectors \(\mathbf{a}=3 \hat{i}+2 \hat{j}+2 \hat{k}, \mathbf{b}=18 \hat{i}-22 \hat{j}-5 \hat{k}\) and make an obtuse angle with \(\hat{j}\). If \(|\mathbf{x}|=14\), then \(\mathbf{x}=\)
- A \(8 \hat{i}+12 \hat{j}+24 \hat{k}\)
- B \(-8 \hat{i}+6 \hat{j}+24 \hat{k}\)
- C \(8 \hat{i}-12 \hat{j}-24 \hat{k}\)
- D \(-8 \hat{i}-12 \hat{j}+24 \hat{k}\)
Answer & Solution
Correct Answer
(D) \(-8 \hat{i}-12 \hat{j}+24 \hat{k}\)
Step-by-step Solution
Detailed explanation
\[ \mathbf{a}=3 \hat{i}+2 \hat{j}+2 \hat{k}, \mathbf{b}=18 \hat{i}-22 \hat{j}-5 \hat{k} \] \(\mathbf{x}\) is perpendicular to \(\mathbf{a}\) and \(\mathbf{b}\). \(\therefore \mathbf{x}\) is parallel to \((\mathbf{a} \times \mathbf{b})\). Now,…
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