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AP EAMCET · Maths · Continuity and Differentiability

If \(f(x)=\left\{\begin{array}{cl}1+6 x-3 x^2, & x \leq 1 \\ x+\log _2\left(b^2+7\right), & x>1\end{array}\right.\) is continuous at all real \(x\), then \(b=\)

  1. A \(\pm {1}\)
  2. B 0
  3. C \(\pm {5}\)
  4. D \(\pm {2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\pm {1}\)

Step-by-step Solution

Detailed explanation

\(f(x)= \begin{cases}1+6 x-3 x^2, & x \leq 1 \\ x+\log _2\left(b^2+7\right), & x>1\end{cases}\) Since \(f(x)\) is continuous at \(x=1\), Hence…