AP EAMCET · Maths · Trigonometric Ratios & Identities
If \(630^{\circ} < \theta < 810^{\circ}\) and \(\tan \theta=-\frac{7}{24}\), then \(\cos \left(\frac{\theta}{4}\right)=\)
- A \(-\sqrt{\frac{7+5 \sqrt{2}}{10 \sqrt{2}}}\)
- B \(\sqrt{\frac{7+5 \sqrt{2}}{2 \sqrt{2}}}\)
- C \(-\sqrt{\frac{5 \sqrt{2}-7}{10 \sqrt{2}}}\)
- D \(\sqrt{\frac{5 \sqrt{2}-7}{2 \sqrt{2}}}\)
Answer & Solution
Correct Answer
(A) \(-\sqrt{\frac{7+5 \sqrt{2}}{10 \sqrt{2}}}\)
Step-by-step Solution
Detailed explanation
\(630^{\circ} \(\cos \theta = \frac{24}{25}\) (since \(\theta\) is in Q4 equivalent, \(\cos \theta > 0\)) \(315^{\circ}…
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