AP EAMCET · Maths · Hyperbola
If the equation of the tangent drawn at \((h, k)\) to the hyperbola \(\frac{(\mathrm{x}-1)^2}{1}-\frac{(\mathrm{y}-2)^2}{2}=1\) is \(\mathrm{x}=2\), then \(\mathrm{h}+\mathrm{k}=\)
- A \(0\)
- B \(4\)
- C \(-4\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
Given equation of hyperbola is \(\begin{aligned} & \frac{(x-1)^2}{1}-\frac{(y-2)^2}{2}=1 ... (i)\\ & \Rightarrow 2(x-1)-(y-2) \frac{d y}{d x}=0 \Rightarrow \frac{d y}{d x}=\frac{2(x-1)}{y-2} ... (ii) \end{aligned}\) Given equation of tangent is \(x=2\), so, slope…
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