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AP EAMCET · Chemistry · Chemical Kinetics

For a first order reaction, the concentration of reactant was reduced from \(0.03 \mathrm{~mol} \mathrm{~L}^{-1}\) to \(0.02 \mathrm{~mol} \mathrm{~L}^{-1}\) in 25 min . What is its rate (in \(\left.\mathrm{mol} \mathrm{L}^{-1}, s^{-1}\right)\) ?

  1. A \(6.667 \times 10^{-6}\)
  2. B \(4 \times 10^{-4}\)
  3. C \(6.667 \times 10^{-4}\)
  4. D \(4 \times 10^{-6}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(6.667 \times 10^{-6}\)

Step-by-step Solution

Detailed explanation

Given :- Time \(=25 \times 60 \mathrm{sec} .=25 \mathrm{~min}\) Concentration of Reactant \(=0.03 \mathrm{~mol} \mathrm{~L}^{-1}\) Concentration of product \(=0.02 \mathrm{~mol} \mathrm{~L}^{-1}\) Rate…