AP EAMCET · Maths · Application of Derivatives
A kind of bacteria grows by \(t^3\) in \(t \mathrm{~s}\). Time taken for the rate of growth of the bacteria to become 1200 per \(s\) is
- A \(10 \mathrm{~s}\)
- B \(20 \mathrm{~s}\)
- C \(40 \mathrm{~s}\)
- D \(400 \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(20 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given, \(\frac{d N}{d t}=t^3,\) When, rate of growth is 1200 we have,…
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