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AP EAMCET · Maths · Matrices

If \(A=\left[\begin{array}{ccc}2 & 1 & 3 \\ -1 & 2 & 0 \\ 4 & 1 & 3\end{array}\right], B=\left[\begin{array}{lll}3 & 2 & 1 \\ 1 & 2 & 3 \\ 3 & 1 & 0\end{array}\right]\), then \(\operatorname{det}\left(2 B^{-1} A^{-1}\right)\) is equal to

  1. A \(\frac{1}{6}\)
  2. B \(\frac{-1}{24}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{-1}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{-1}{6}\)

Step-by-step Solution

Detailed explanation

\text { (d) } \begin{aligned} A & =\left[\begin{array}{ccc} 2 & 1 & 3 \\ -1 & 2 & 0 \\ 4 & 1 & 3 \end{array}\right], B=\left[\begin{array}{lll} 3 & 2 & 1 \\ 1 & 2 & 3 \\ 3 & 1 & 0 \end{array}\right] \\ A^{-1} & =\frac{1}{|A|} \operatorname{adj} A, B^{-1}=\frac{1}{|B|}…