AP EAMCET · Maths · Circle
If \(\left(\frac{1}{10}, \frac{-1}{5}\right)\) is the inverse point of a point \((-1,2)\) with respect to the circle \(x^2+y^2-2 x+4 y+c=0\) then \(c=\)
- A 4
- B -4
- C 2
- D -2
Answer & Solution
Correct Answer
(B) -4
Step-by-step Solution
Detailed explanation
\(C=(1,-2)\) \(r^2=1^2+(-2)^2-c = 5-c\) \(CP^2=(-1-1)^2+(2-(-2))^2 = (-2)^2+4^2 = 4+16 = 20\) \(CQ^2=(\frac{1}{10}-1)^2+(-\frac{1}{5}-(-2))^2 = (-\frac{9}{10})^2+(\frac{9}{5})^2 = \frac{81}{100}+\frac{324}{100} = \frac{405}{100}\)…
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