AP EAMCET · Maths · Limits
\(\lim _{n \rightarrow \infty}\left\{\frac{1}{n+m}+\frac{1}{n+2 m}+\frac{1}{n+3 m}+\ldots+\frac{1}{n+n m}\right\}=\)
- A \(\frac{\log _8(m)}{m}\)
- B \(\frac{\log _e(1+m)}{1+m}\)
- C \(\frac{\log _e(1+m)}{m}\)
- D \(\frac{\log _e(1+m)}{1-m}\)
Answer & Solution
Correct Answer
(C) \(\frac{\log _e(1+m)}{m}\)
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