AP EAMCET · Maths · Straight Lines
If two distinct points lying at a unit distance from \(4 \mathrm{x}+3 \mathrm{y}-10=0\) and passing through \(\mathrm{x}+\mathrm{y}=4\) are separated by a distance \(\mathrm{d}\), then the value of \(\mathrm{d}\) is
- A \(10 \sqrt{2}\)
- B \(10\)
- C \(\sqrt{2}\)
- D \(200\)
Answer & Solution
Correct Answer
(A) \(10 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
The point lie on \(x+y=4\) Coordinates of point \((\alpha, 4-\alpha)\) Distnace from \(4 x+3 y-10=0\) is 1 \(\left|\frac{4 \alpha+3(4-\alpha)-10}{\sqrt{4^2+3^2}}\right|=1\) \(\left|\frac{4 \alpha+12-3 \alpha-10}{5}\right|=1\)…
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