AP EAMCET · Maths · Probability
For \(k=1,2,3\) the box \(B_k\) contains \(k\) red balls and \((k+1)\) white balls. Let \(P\left(B_1\right)=\frac{1}{2}\), \(P\left(B_2\right)=\frac{1}{3}\) and \(P\left(B_3\right)=\frac{1}{6}\). A box is selected at random and a ball is drawn from it. If a red ball is drawn, then the probability that it has come from box \(B_2\), is
- A \(\frac{35}{78}\)
- B \(\frac{14}{39}\)
- C \(\frac{10}{13}\)
- D \(\frac{12}{13}\)
Answer & Solution
Correct Answer
(B) \(\frac{14}{39}\)
Step-by-step Solution
Detailed explanation
In a box, \[ \begin{aligned} B_1 & =1 R, 2 W \\ B_2 & =2 R, 3 W \\ \text { and } \quad B_3 & =3 R, 4 W \end{aligned} \] Also, given that,…
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