AP EAMCET · Maths · Permutation Combination
The number of 5 digit odd numbers greater than 40,000 that can be formed by using \(3,4,5,6,7,0\) so that at least one of its digit must be repeated is
- A 2592
- B 240
- C 3032
- D 2352
Answer & Solution
Correct Answer
(D) 2352
Step-by-step Solution
Detailed explanation
Since 5-digit numbers must be odd, their last digit is 3,5 , or 7 . We can choose the last digit any of 3 ways, as 3,5 or 7 We can then choose the first digit any of 4 ways, as 4,5 , 6 or 7 We choose the second digit as any of the 6 digits We choose the third digit as any of the…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- Find the absolute maximum of \(x^{40}-x^{20}\) on the interval \([0,1]\).AP EAMCET 2021 Hard
- Let \([t]\) represents the greatest integer not exceeding \(t\), Then the number of discontinuous points of \(\left[10^x\right]\) in \((0,10)\) isAP EAMCET 2023 Easy
- \(\int \frac{1}{\cos x}\left[\frac{1}{\sin x}-\frac{1}{\sin x+3 \cos x}\right] d x=\)AP EAMCET 2025 Medium
- If \(\mathbf{a}=4 \hat{i}+6 \hat{j}, \mathbf{b}=3 \hat{j}+4 \hat{k}\) and \(\mathbf{c}\). is the projection vector of \(\mathbf{a}\) on \(\mathbf{b}\), then \(\mathbf{c}\) and \(|\mathbf{c}|\) respectively areAP EAMCET 2022 Medium
- If the point lies on the plane and thenAP EAMCET 2018 Easy
- If the acute angle between lines is , thenAP EAMCET 2021 Medium
More PYQs from AP EAMCET
- If , thenAP EAMCET 2022 Hard
- Each nuclear fission of \({ }^{235} \mathrm{U}\) releases 200 MeV of energy. If a reactor generates 1 MW power, then the rate of fission in the reactor isAP EAMCET 2025 Medium
- If the vectors \(\mathbf{i}-2 x \mathbf{j}-3 y \mathbf{k}\) and \(\mathbf{i}+3 x \mathbf{j}+2 y \mathbf{k}\) are orthogonal to each other, then the locus of the point \((x, y)\) isAP EAMCET 2011 Easy
- A crystal of intrinsic silicon at room temperature has a carrier concentration of \(1.6 \times 10^{16} / \mathrm{m}^3\). If the donor concentration level is \(4.8 \times 10^{20} / \mathrm{m}^3\), then the concentration of holes in the semiconductor isAP EAMCET 2014 Easy
- \(\lim _{n \rightarrow \infty} \frac{1}{n}\left(\frac{1}{e^{1 / n}}+\frac{1}{e^{2 / n}}+\frac{1}{e^{3 / n}}+\ldots+\frac{1}{e^2}\right)=\)AP EAMCET 2023 Medium
- If \(\left(\frac{\cos \theta+i \sin \theta}{\sin \theta+i \cos \theta}\right)^{2024}+\left(\frac{1+\cos \theta+i \sin \theta}{1-\cos \theta+i \sin \theta}\right)^{2025}=x+i y\), then the value of \(x+y\) at \(\theta=\frac{\pi}{2}\) isAP EAMCET 2025 Medium