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AP EAMCET · Maths · Pair of Lines

One line of the pair of lines \(x^2+x y-2 y^2=0\) is perpendicular to one line of the pair of lines \(3 y^2-5 x y-2 x^2=0\). If the combined equation of the two lines other than those two perpendicular lines is \(a x^2+2 h x y+b y^2=0\), then \(a+2 h+b=\)

  1. A -1
  2. B 1
  3. C 0
  4. D -5
Verified Solution

Answer & Solution

Correct Answer

(C) 0

Step-by-step Solution

Detailed explanation

\((x-y)(x+2y)=0\) \((2x-y)(x+3y)=0\) One line \\(x+2y=0\) (slope \(-1/2\)) is perpendicular to one line \\(2x-y=0\) (slope \(2\)). The other two lines are \\(x-y=0\) and \\(x+3y=0\). Combined equation: \((x-y)(x+3y)=0\) \(x^2+3xy-xy-3y^2=0\) \(x^2+2xy-3y^2=0\) Comparing with…