AP EAMCET · Maths · Circle
Consider the point \(P(\alpha, \beta)\) on the line \(2 x+y=1\). If the \(P\) and \((3,2)\) are conjugate points with respect to the circle \(x^2+y^2=4\), then \(\alpha+\beta=\)
- A 3
- B -1
- C -5
- D 7
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
Polar of point \((3,2)\) w.r.t. circle \(x^2+y^2=4 \text { is } T_1=0 \Rightarrow 3 x+2 y=4\) Since, \((3,2)\) and \(P(\alpha, \beta)\) are conjugate point. So, polar of \((3,2)\) passes through \(P(\alpha, \beta) \Rightarrow 3 \alpha+2 \beta=4\) ...(i) Also,…
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