AP EAMCET · Maths · Parabola
For any non-zero real value of \(m\), the equation of the parabola to which the line \(m x-y+10+m^2=0\) is a tangent, is
- A \(x^2=y-10\)
- B \(y^2=4(x-2)\)
- C \(x^2=-4(y-10)\)
- D \(x^2=-4 y\)
Answer & Solution
Correct Answer
(C) \(x^2=-4(y-10)\)
Step-by-step Solution
Detailed explanation
Given, equation of tangent to the parabola is \(\begin{aligned} m x-y+\left(10+m^2\right) & =0 \\ m^2+m x+(10-y) & =0 \end{aligned}\) Since, above line is tangent, then \(D=0\)…
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