AP EAMCET · Maths · Properties of Triangles
In triangle \(A B C\), if \(\frac{b+c}{9}=\frac{c+a}{10}=\frac{a+b}{11}\), then \(\frac{\cos A+\cos B}{\cos C}=\)
- A \(\frac{9}{10}\)
- B \(\frac{10}{11}\)
- C \(\frac{11}{12}\)
- D \(\frac{12}{13}\)
Answer & Solution
Correct Answer
(C) \(\frac{11}{12}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Let } \frac{b+c}{9}=\frac{c+a}{10}=\frac{a+b}{11}=k \\ & \Rightarrow b+c=9 k, c+a=10 k \text { and } a+b=11 k \\ & \text { and } a+b+c=15 k \\ & \therefore a=6 k, b=5 k \text { and } c=4 k \\ & \because \frac{\cos A+\cos B}{\cos…
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