AP EAMCET · Maths · Properties of Triangles
If \(\cos A=\frac{-60}{61}\) and \(\tan B=-\frac{7}{24}\) and neither \(A\) nor \(B\) is the second quadrant, then the angle \(A+\frac{B}{2}\) lies in the quadrant
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
It is given that \(\cos A=-\frac{60}{61}\) and \(\tan B=\frac{-7}{24}\) and neither \(A\) nor \(B\) is in the second quadrant, then \(A\) and \(B\) will be in third and fourth quadrant respectively. So, \(\frac{B}{2}\) will be in second quadrant. Now,…
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