AP EAMCET · Maths · Ellipse
The length of the latus rectum of \(16 x^2+25 y^2=400\) is
- A \(\frac{25}{2}\)
- B \(\frac{25}{4}\)
- C \(\frac{16}{2}\)
- D \(\frac{32}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{32}{5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & 16 x^2+25 y^2=400 \Rightarrow \frac{x^2}{25}+\frac{y^2}{16}=1 \\ a^2= & 25, b^2=16 \end{aligned}\) Length of lectus rectum \(=\frac{2 b^2}{a}=\frac{32}{5}\)
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