ExamBro
ExamBro
AP EAMCET · Maths · Indefinite Integration

\(\int \frac{d x}{(x-3)^{\frac{4}{5}}(x+1)^{\frac{6}{5}}}=\)

  1. A \(\frac{5}{4} \sqrt[5]{\frac{x-3}{x+1}}+C\)
  2. B \(\frac{5}{4}\left(\frac{x+1}{x-3}\right)^{\frac{1}{5}}+C\)
  3. C \(\frac{1}{5}\left(\frac{x-3}{x+1}\right)^{\frac{1}{5}}+C\)
  4. D \(\frac{5}{4}\left(\frac{x-3}{x+4}\right)^{\frac{4}{5}}+C\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{5}{4} \sqrt[5]{\frac{x-3}{x+1}}+C\)

Step-by-step Solution

Detailed explanation

Let \(I=\int \frac{d x}{(x+1)^{\frac{6}{5}}(x-3)^{\frac{4}{5}}}\) \(I=\int \frac{d x}{(x+1)^2\left(\frac{x-3}{x+1}\right)^{\frac{4}{5}}}\) On putting \(\frac{(x-3)}{(x+1)}=t\), then \(d t=\frac{4}{(x+1)^2} d x\)…