AP EAMCET · Maths · Indefinite Integration
\(\int \frac{d x}{(x-3)^{\frac{4}{5}}(x+1)^{\frac{6}{5}}}=\)
- A \(\frac{5}{4} \sqrt[5]{\frac{x-3}{x+1}}+C\)
- B \(\frac{5}{4}\left(\frac{x+1}{x-3}\right)^{\frac{1}{5}}+C\)
- C \(\frac{1}{5}\left(\frac{x-3}{x+1}\right)^{\frac{1}{5}}+C\)
- D \(\frac{5}{4}\left(\frac{x-3}{x+4}\right)^{\frac{4}{5}}+C\)
Answer & Solution
Correct Answer
(A) \(\frac{5}{4} \sqrt[5]{\frac{x-3}{x+1}}+C\)
Step-by-step Solution
Detailed explanation
Let \(I=\int \frac{d x}{(x+1)^{\frac{6}{5}}(x-3)^{\frac{4}{5}}}\) \(I=\int \frac{d x}{(x+1)^2\left(\frac{x-3}{x+1}\right)^{\frac{4}{5}}}\) On putting \(\frac{(x-3)}{(x+1)}=t\), then \(d t=\frac{4}{(x+1)^2} d x\)…
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