AP EAMCET · Maths · Indefinite Integration
\(\int \frac{\mathrm{dx}}{(\mathrm{x}+1) \sqrt{\mathrm{x}^2+1}}=\)
- A \(\frac{1}{\sqrt{2}} \operatorname{Sinh}^{-1}\left(\frac{1+x}{1-x}\right)+c\)
- B \(\frac{1}{\sqrt{2}} \operatorname{Sinh}^{-1}\left(\frac{1-x}{1+x}\right)+c\)
- C \(-\frac{1}{\sqrt{2}} \operatorname{Sinh}^{-1}\left(\frac{1-x}{1+x}\right)+c\)
- D \(-\frac{1}{\sqrt{2}} \operatorname{Sinh}^{-1}\left(\frac{1+x}{1-x}\right)+c\)
Answer & Solution
Correct Answer
(C) \(-\frac{1}{\sqrt{2}} \operatorname{Sinh}^{-1}\left(\frac{1-x}{1+x}\right)+c\)
Step-by-step Solution
Detailed explanation
Let \(x+1 = \frac{1}{t}\), so \(x = \frac{1}{t}-1\) and \(dx = -\frac{1}{t^2} dt\). \(\sqrt{x^2+1} = \sqrt{\left(\frac{1}{t}-1\right)^2+1} = \sqrt{\frac{1}{t^2}-\frac{2}{t}+1+1} = \frac{\sqrt{2t^2-2t+1}}{t}\).…
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