AP EAMCET · Maths · Circle
If the two circles \((x-1)^2+(y-3)^2=r^2\) and \(x^2+y^2-8 x+2 y+8=0\) intersect at two distinct points, then
- A 2 < r < 8
- B \(1 < r < 9\)
- C r = 2
- D r = 8
Answer & Solution
Correct Answer
(A) 2 < r < 8
Step-by-step Solution
Detailed explanation
Equation of given circles \[ \begin{aligned} S_1:(x-1)^2+(y-3)^2 & =r^2 \\ \text { and } & S_2:(x-4)^2+(y+1)^2=3^2 \end{aligned} \] If circles \(S_1\) and \(S_2\) intersect at two distinct points, then…
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