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AP EAMCET · Maths · Inverse Trigonometric Functions

If x=sin2tan-12, y=cos2tan-13, z=sec3tan-14 then

  1. A x<y<z
  2. B y<z<x
  3. C z<x<y
  4. D z<y<x
Verified Solution

Answer & Solution

Correct Answer

(D) z<y<x

Step-by-step Solution

Detailed explanation

We know, 2tan-1x=sin-1(2x1+x2) =cos-1(1-x21+x2)=sec-1(1+x21-x2) ∴x=sin2tan-12  = sinsin-1221+22 = 45 y=cos2tan-13 = coscos-1(1-321+32) = -45 z=sec2tan-14 secsec-1(1+421-42) = -54 ∴z<y<x