AP EAMCET · Maths · Probability
A die is rolled three times. The probability of getting their sum equal to a prime number of the form \(4 n+1\) is
- A \(\frac{1}{6}\)
- B \(\frac{7}{36}\)
- C \(\frac{5}{36}\)
- D \(\frac{11}{36}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{36}\)
Step-by-step Solution
Detailed explanation
We obtain following prime sum in three throws of dice; 3, 5, 7, 11, 13 and 17 And sum in from of \(4 m+1\) are, 5, 13 and 17 Following are favourable outcomes for above sums…
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